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	<title>Comments on: UCT MAM1000 lecture notes part 28 – complex numbers part vi</title>
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	<description>All about maths in Africa</description>
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		<title>By: Jonathan Shock</title>
		<link>http://www.mathemafrica.org/?p=11369#comment-319</link>
		<dc:creator><![CDATA[Jonathan Shock]]></dc:creator>
		<pubDate>Sun, 06 Sep 2015 15:35:57 +0000</pubDate>
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		<description><![CDATA[Hi Grant, indeed it should be \sqrt{1^2+1^2} as you rightly point out. Many thanks,

J]]></description>
		<content:encoded><![CDATA[<p>Hi Grant, indeed it should be \sqrt{1^2+1^2} as you rightly point out. Many thanks,</p>
<p>J</p>
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		<title>By: grant wilson</title>
		<link>http://www.mathemafrica.org/?p=11369#comment-318</link>
		<dc:creator><![CDATA[grant wilson]]></dc:creator>
		<pubDate>Sun, 06 Sep 2015 11:22:26 +0000</pubDate>
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		<description><![CDATA[We know that the modulus of 1+i is \sqrt{1^2+i^2}=\sqrt{2}, and the argument is \arctan \left(\frac{1}{1}\right)+2n\pi with n\in {\mathbb Z}. Thus, we can write our equation as..

isnt the statement suppose to read &quot;We know that the modulus of 1+i is  \sqrt{a^2+b^2}=\sqrt{2}&quot; not &quot; \sqrt{1^2+i^2}=\sqrt{2}&quot; as this would give us 0 and not \sqrt{2}.]]></description>
		<content:encoded><![CDATA[<p>We know that the modulus of 1+i is \sqrt{1^2+i^2}=\sqrt{2}, and the argument is \arctan \left(\frac{1}{1}\right)+2n\pi with n\in {\mathbb Z}. Thus, we can write our equation as..</p>
<p>isnt the statement suppose to read &#8220;We know that the modulus of 1+i is  \sqrt{a^2+b^2}=\sqrt{2}&#8221; not &#8221; \sqrt{1^2+i^2}=\sqrt{2}&#8221; as this would give us 0 and not \sqrt{2}.</p>
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